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Let the probability of taking the cab, train or car be p(cab), p(train) and p(cab). If they are equally likely then it will be 1/3 but if not it doesn't matter as long as they sum to 1. Now what is the probability of taking a cab given that God knows you will take the cab, i.e. the conditional probability. p(cab/given God knows) = P(cab and God knows)/p(God knows). p(God knows) must be equal to 1 since God knows everything and there is no uncertainity in it. So in this case p(cab/given God knows)=p(cab) the unconditional probability of you taking a cab. Which means that you are free to choose your mode of transport. The fact that God knows does not change the probability of you taking whatever method you choose. Right? |
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Yes by John Doe 666, 2001, Nov 26
Hi JohnDoe triple 6, by Interested , 2001, Nov 26
my point by John Doe 666, 2001, Nov 27
Hi Joe^6 by Interested , 2001, Nov 27
engine by John Doe 666, 2001, Nov 28
Yah, you're right and so .... by Interested , 2001, Nov 28
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